Files
postgres-web/pgweb/misc/views.py
Magnus Hagander fd37389a3b Replace NavContext and render_to_response with render_pgweb
render_to_response does not work on newer django, so it needs to be
replaced. And using a speicfic context actually overcomplicates things,
it's easier to just use a wrapper function. For those cases where we
don't need NavContext, just use render() (the new shortcut function from
django), which also removes the need to use RequestContext.
2018-03-10 10:38:11 -05:00

68 lines
1.9 KiB
Python

from pgweb.util.decorators import login_required
from django.http import HttpResponse
from django.db import connection
from django.conf import settings
import os
from pgweb.util.contexts import render_pgweb
from pgweb.util.helpers import template_to_string
from pgweb.util.misc import send_template_mail
from pgweb.core.models import Version
from forms import SubmitBugForm
@login_required
def submitbug(request):
if request.method == 'POST':
form = SubmitBugForm(request.POST)
if form.is_valid():
c = connection.cursor()
c.execute("SELECT nextval('bug_id_seq')")
bugid = c.fetchall()[0][0]
send_template_mail(
settings.BUGREPORT_NOREPLY_EMAIL,
settings.BUGREPORT_EMAIL,
'BUG #%s: %s' % (bugid, form.cleaned_data['shortdesc']),
'misc/bugmail.txt',
{
'bugid': bugid,
'bug': form.cleaned_data,
},
usergenerated=True,
cc=form.cleaned_data['email'],
replyto='%s, %s' % (form.cleaned_data['email'], settings.BUGREPORT_EMAIL),
sendername="PG Bug reporting form",
)
return render_pgweb(request, 'support', 'misc/bug_completed.html', {
'bugid': bugid,
})
else:
form = SubmitBugForm(initial={
'name': '%s %s' % (request.user.first_name, request.user.last_name),
'email': request.user.email,
})
versions = Version.objects.filter(supported=True)
return render_pgweb(request, 'support', 'base/form.html', {
'form': form,
'formitemtype': 'bug report',
'operation': 'Submit',
'form_intro': template_to_string('misc/bug_header.html', {
'supportedversions': versions,
}),
})
# A crash testing URL. If the file /tmp/crashtest exists, raise a http 500
# error. Otherwise, just return a fixed text response
def crashtest(request):
if os.path.exists('/tmp/crashtest'):
raise Exception('This is a manual test of a crash!')
else:
return HttpResponse('Crash testing disabled', content_type='text/plain')